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Wednesday, August 27, 2014

SSRS Report Issue- Toggle Item Visibility default as Expanded with + sign

Issue- Toggled Item Text Box Sign in Report while giving Default as expanded showing + Sign instead of -.

Issue Description-We Created a SSRS Report which used to show Project Name and Employee assigned to the Projects .Default Nature of Report was expanded all but while previewing the Report the toggle sign appears as + sign in below Screenshot.

Test Report Highlighting Issue Screenshot.



Issue Solution. To fix this Issue below are the steps.

1. Select  your toggle Item (i.e. Text box  ) which is showing the + Sign.
           2.    Go to Properties of Selected Text box (Right Hand Side Properties ).
3.  Change the IntialToggleState Property from False to True as in below Screenshot.




4.       Preview the Report .Now on Default Expanded all  Report will show the correct Sign i.e (-).





 



Monday, August 25, 2014

Converting Column Values as Comma Separated String based on condition in SQL

Requirement- Our Requirement was Employee which are working on same Projects OR Employee who are assigned to same projects should come as a comma separated string in a single row for each Project from Project table  like below..

Output Required

ProjectName           name
Project1                rakesh, mukesh, sukesh
Project2                ajit, surjit


Below is test Project  table structure.

create table Projects
(Projectname varchar(200),Empname varchar(200)
)

insert into Projects values ('Project1','rakesh'),('Project1','mukesh'),('Project1','sukesh'),('Project2','ajit'),('Project2','surjit')

select * from Projects

Projectname      Empname
Project1            rakesh
Project1            mukesh
Project1            sukesh
Project2            ajit
Project2            surjit

In the above Projects table

For Project1-Employee assigned-Rakesh,  Mukesh,  Sukesh
For Project2 –Employee assigned-Ajit, Surjit

Each Row in Project table is showing Project Name and employee name assigned to that project.

We want the output like all employee names assigned to same project  should come as comma separated value as an string in a single row for each project.

So below is the Script  that convert column values as comma separated values

--create table Projects
--(Projectname varchar(200),Empname varchar(200)
--)

--
--insert into Projects values ('Project1','rakesh'),('Project1','mukesh'),('Project1','sukesh'),('Project2','ajit'),('Project2','surjit')

--Below script will show column values as comma separated string based on condition

declare @ProjectName nvarchar(100)
declare @name nvarchar(200)
declare @newProjectName nvarchar(100)
declare @newname nvarchar(100)
set @newProjectName='0'
set @newname ='0'

create table #tbl (ProjectName varchar(200) ,name varchar(100))

declare C cursor  for select Projectname,Empname from Projects
open  c
fetch next from c into @ProjectName,@name
set @newProjectName=@ProjectName
while @@FETCH_STATUS =0
begin
if @newProjectName= @ProjectName
begin
  if (@newname ='0')
 begin
   set @newname =@name
 end
   else
   begin
   set @newname =@newname  + ', '+ @name
end
end

if @newProjectName<>@ProjectName
begin
insert into #tbl values(@newProjectName,@newname )
set @newProjectName=@ProjectName
set @newname =@name

end
fetch next from c into @ProjectName,@name
end

if @newProjectName=@ProjectName
begin
insert into #tbl values(@newProjectName,@newname )

end

close c
deallocate c
select * from #tbl
drop Table #tbl


Script Output 

ProjectName                 Name
Project1                        rakesh, mukesh, sukesh
Project2                        ajit, surjit




Saturday, July 26, 2014

We cannot locate a server to load the workbook data model

We cannot locate a server to load the workbook data model

Issue-The Error was coming in SharePoint 2013 site when refreshing or clicking on any slicer of  the Power table Report in excel 2013 workbook.

Issue Cause-This issue occurs because the Analysis Services instance has not been configured in the Central Administration site.

Issue Solutions-Restart your SQL Server Analysis Server (PowerPivot) and Reset the IIS.


In most of the case above will fix your above Issue.

If in case the above method will not fix the Issue then configure the Excel Services service application on the SharePoint server. To do this, follow these steps:

1.       In the Application Management  section of the Central Administration home page, click Manage service applications.
2.       On the Manage Service Applications page, click the Excel Services service application that you want to configure.
3.       On the Manage Excel Services page, click Data Model.
4.       Click Add Server.
5.       In the Server Name box, type the name of the Analysis Services instance that you want to add.
6.       Click OK.


Monday, July 21, 2014

Unable to open the physical file in SQL

                Unable to open the physical file in SQL

Issue-Issue in SQL while Attaching MDF File or Restoring Backup file from some location.

Error1
Msg 5120, Level 16, State 101, Line 1
Unable to open the physical file "C:\ DB \AdventureWorksDW2012_Data (1).mdf". Operating system error 2: "2(The system cannot find the file specified.)".

Error 2
Msg 5120, Level 16, State 101, Line 1
Unable to open the physical file "C:\ DB \AdventureWorksDW2012_Data.mdf". Operating system error 32: "32(failed to retrieve text for this error. Reason: 15105)".


Issue Description-While attaching the Database  mdf file in sql server we were getting these above errors.

--Attaching MDF File without ldf file
CREATE DATABASE AdventureWorksDW2012
ON (FILENAME = 'C:\DB\AdventureWorksDW2012_Data.mdf')
FOR ATTACH_REBUILD_LOG ;

Error

Msg 5120, Level 16, State 101, Line 1
Unable to open the physical file "C:\DB\AdventureWorksDW2012_Data (1).mdf". Operating system error 2: "2(The system cannot find the file specified.)".

Issue Solution

-Run SSMS as an Administrator
-Restart SQL Server

Now you will be able to attach the DB Successfully.

Run your query again 

--Attaching MDF File without ldf file
CREATE DATABASE AdventureWorksDW2012
ON (FILENAME = 'C:\DB\AdventureWorksDW2012_Data.mdf')
FOR ATTACH_REBUILD_LOg

Output.It will attach the mdf file and will create a new ldf (log file) in same location 
with the message below.

File activation failure. The physical file name "C:\Program Files\Microsoft SQL Server\MSSQL11.MSSQLSERVER\MSSQL\DATA\AdventureWorksDW2012_log.ldf" may be incorrect.
New log file 'C:\DB\AdventureWorksDW2012_log.ldf' was created.

NOTE: If after Running SQL as Administrator and Restarting the sql server won’t work for you then check for permission in your folder where you have kept your mdf or back file then go to “Sharing and Security of that folder and Allow-Full control.

Tuesday, July 8, 2014

T-SQL Script to perform DML Operations (Select, Insert, Update and Delete) based on DB Name

T-SQL script that will Perform DML Operations (Select, Insert, Update and Delete) based on DB Name


Requirement-We were working with Different customers DB where different customers were having Different DB Names but the table name and Structure of Tables were same.

So our requirement was through same web application we need to perform DML Operations (Select, Insert, Update and Delete) based on DB Name passed from front end (i.e. web application).
For Eg

DB-Customer-X
Tables-Employee, Products, Product_Description, Customers……….

DB-Customer-Y
Tables-Employee, Products, Product_Description, Customers……….

DB-Customer-Z
Tables-Employee, Products, Product_Description, Customers……….

So below I created a Stored Procedure Script that used to perform DML in different db based on DB Name passed from Front end

So Below is the Script with two test DB and one Employee Table

--Creating two test DB
Create database Test1
Create Database Test2

--Run Table Script in both the Database
CREATE TABLE [dbo].[Employee1](
     [Empid] [int] IDENTITY(1,1) NOT NULL,
     [EmpName] [nvarchar](50) NULL,
     [EmpSalary] [float] NULL,
 CONSTRAINT [PK_Employee1] PRIMARY KEY CLUSTERED
(
     [Empid] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]

GO

Stored Procedure Script that will will Perform DML Operations (Select, Insert, Update and Delete) based on DB Name Passed.

 --Script Code
--Run this Procedure in DB with which your web application is connected
Create PROCEDURE [dbo].[proc_db_test]
 (
 --Passing DB Name
@dbname varchar(100)=null,
--For Passing Operation insert update delete select
@Operation varchar(100)=null,
--Passing table values
@EmpId int =null,
@EmpName nvarchar(200)=null,
@EmpSalary float=null
 )
 AS
 BEGIN
IF db_id(@dbname) IS NULL
 BEGIN
RAISERROR ('Database %s does not exists!', 16,1, @dbname)
RETURN
END

if @Operation='INSERT'
begin

  EXEC('INSERT INTO '+@dbname+' .dbo.Employee1(EmpName,EmpSalary)
        VALUES('''+@EmpName+''','''+@EmpSalary+''')')

END
else if @Operation='UPDATE'
begin
 exec('update ' +@dbname+'.dbo. Employee1
set EmpName= '''+@EmpName+'''
,EmpSalary= '''+@EmpSalary+''' where EmpId='''+@EmpId+'''')
END
else if  @Operation='DELETE' 
begin
exec('Delete  from  ' +@dbname+'.dbo.Employee1  where EmpId='''+@EmpId+'''')
end
else  if @Operation='SELECTDETAILS'
begin
exec('select * from   ' +@dbname+'.dbo.Employee1  where EmpId='''+@EmpId+'''')
end
else if @Operation='SELECTALL'
begin
exec('select * from ' +@dbname+'.dbo.Employee1 order by Empid')
end
End


Test the Script

Insert Operation in both DB
--Procedure will have following inputs
--Proj_DB_Test DBName OPeration,EmpID,EMPName,EmpSalary

Exec  [dbo].[proc_db_test] 'Test1','Insert',1,'RK','15000'

--Test1 DB Test
Select * from test1.dbo.Employee1

Output
Empid  EmpName       EmpSalary
1          RK        15000

--Procedure will have following inputs
--Proj_DB_Test DBName OPeration,EmpID,EMPName,EmpSalary

Exec  [dbo].[proc_db_test] 'Test2','Insert',1,'RK1','20000'

--Test2 DB Test
Select * from test2.dbo.Employee1


Output
Empid EmpName    EmpSalary
1    RK1  20000


Test Update Operation in both DB

--Updating Name in Test1 DB
Exec  [dbo].[proc_db_test] 'Test1','UPdate',1,'RK_new','15000'

Output
Empid EmpName    EmpSalary
1    RK_new     15000



Test Delete Operation in both DB
--For Testing Delete Operation we will insert one more record in any of DB

--Insert
Exec  [dbo].[proc_db_test] 'Test1','Insert',2,'RK_1','10000'

Output

Empid EmpName    EmpSalary
1    RK_new     15000
2    RK_1 10000

--Deleting above newely added Record
Exec  [dbo].[proc_db_test] 'Test1','Delete',2

Output

Empid EmpName    EmpSalary
1    RK_new     15000


Test Select Operations in both DB
--Test Specific Records of Both DB Employee Table by passing Employee ID

Exec  [dbo].[proc_db_test] 'Test1','SELECTDETAILS',2

Output

Empid EmpName    EmpSalary
1    RK_new     15000



Exec  [dbo].[proc_db_test] 'Test2','SELECTDETAILS',1

Output 
Empid EmpName    EmpSalary
1    RK1  20000

Test Select all Operation in both DB
--Test all Records of Both DB Employee Table

Exec  [dbo].[proc_db_test] 'Test1','SELECTALL'

Output

Empid EmpName    EmpSalary
1    RK_new     15000

Exec  [dbo].[proc_db_test] 'Test2','SELECTALL'

Output

Empid EmpName    EmpSalary
1    RK1  20000


Testing by Passing DB Name that doesn't exist in server-Will Raise the below error

Exec  [dbo].[proc_db_test] 'Test3','SELECTALL'

Msg 50000, Level 16, State 1, Procedure proc_db_test, Line 16
Database Test3 does not exists!

NOTE:The best use of this script when you have multiple customers having different Databases having same table Names and Same table Structure.




Friday, June 27, 2014

Issue:Unclosed quotation mark after the character string ''.

Unclosed quotation mark after the character string in SQL


Issue:Msg 105, Level 15, State 1, Line 1
Unclosed quotation mark after the character string ''.


Issue Reason: Apostrophe (')  is used in sql to start and end the string.So including  Apostrophe (')  in any string or varchar values will throw the above error.
for eg: if you run below query it will thrown the above error
Select 'Indian's'

Msg 105, Level 15, State 1, Line 1
Unclosed quotation mark after the character string ''.


Solution:To fix this issue you need to add one more Apostrophe (')
Select 'Indian''s'

Output:Indian's

Note :when Inserting the values containing   Apostrophe (') from your web application or system applications into SQL you can replace the Apostrophe (') with double Apostrophe ('') by using Replace Function.

Tuesday, June 24, 2014

Script -Deleting data of all tables of a Database in SQL

Script -Deleting data of all tables of a Database in SQL

The below Script will delete data from all tables of a Database.

Don't test the script in your Primary Database  although for data safety i have the script inside transaction block  and it will rollback all changes.
For tables having Referential Integrity truncate command will not work.So for that we are we are using Delete command.

--Tested and verified in SQL 2008 R2 and SQL2012

Begin tran

-- disable all referential integrity
EXEC sp_MSForEachTable 'ALTER TABLE ? NOCHECK CONSTRAINT ALL'
GO

EXEC sp_MSForEachTable '
 IF OBJECTPROPERTY(object_id(''?''), ''TableHasForeignRef'') = 1
  DELETE FROM ?
 else
  TRUNCATE TABLE ?
'
GO
-- enable all  referential integrity again
EXEC sp_MSForEachTable 'ALTER TABLE ? CHECK CONSTRAINT ALL'
GO
Rollback

Truncate will not Delete the Data if the table have referential Integrity(Foreign key) 
So for table having referential Integrity or foreign key Relation we are using Delete .
Test it by Removing the If condition that is deleting Data of all tables.

Begin tran

-- disable all referential integrity
EXEC sp_MSForEachTable 'ALTER TABLE ? NOCHECK CONSTRAINT ALL'
GO

EXEC sp_MSForEachTable 'TRUNCATE TABLE ?'
GO
-- enable all  referential integrity again
EXEC sp_MSForEachTable 'ALTER TABLE ? CHECK CONSTRAINT ALL'
GO
Rollback

Msg 4712, Level 16, State 1, Line 1
Cannot truncate table 'dbo.Employee' because it is being referenced by a FOREIGN KEY constraint.

Note :Truncate will reset the Identity column but Delete command doesn't  'So in order to Reset the Identity column for tables having Foreign key Relation ship in the above script
Use the below command


DBCC CHECKIDENT('TableName', RESEED, 0)--0 new reseed starting value